A.
Simultaneous Equation
1.
Linear equation
are equations that have one or more unknowns in the first degree.
For example,
2y-3x=5
2.
Non-linear
equations have one or more unknowns in degrees greater than one.
For example: x2+2x+y2-3y=0
3.
Simultaneous
equations consists of two equations that have common solutions, a linear
equation and a non-linear equation
4.
The steps in
solving simultaneous equations are:
Step 1
From the linear
equation, an unknown is expressed in term of the other unknown
Step 2
The unknown is
substituted into the non-linear equation and a quadratic equation in term of
the other unknown is formed
Step 3
Simplify and
solve the quadratic equation to obtain the values of first unknown using factorization or the
quadratic formula
Step 4
Obtain the
values of the second unknown by substituting the values of the first unknown,
one by one, into the linear equation.
Simultaneous linear
equations can be solve by using two method which is
Method 1: Elimination
Or
Method 2: Substitution
Example:
Solve the following simultaneous linear
equations:
x - 3y = 2
3y + x = 8
By using method 1:
x - 3y = 2
(-) x +3y = 8
-6y = -6
y = 1
when the value of y is equal to 1
x - 3(1) = 2
x – 3=2
x = 5
y = 1, x = 5
By using method 2:
x -
3y = 2 ----equation 1
3y
+ x = 8 -----equation 2
From equation 1, express unknown of x in the
equation in terms of the other. Then, a new equation is form.
x – 3y = 2
x = 2 + 3y ------equation 3
Substitute equation 3 into equation 2
3y +
(2+ 3y) =8
6y =
8-2
6y =
6
y =
1
when the value of y is equal to 1,
x= 2 + 3 (1)
= 5
x= 5, y = 1
Simultaneous equations in two unknowns (one linear
equation and one non-linear equation)
x- y = -2
x2 – 6y2 = -17
x – y =-2
x = -2
+y (Express one unknown in the equation in
terms of the other)
(-2 +y)2 -6y2 = -17 (Substitute
unknow in equation 1 into non- linear equation to obtain quadratic equation in
one unknown)
(-2 + y)( -2+y) -6y =
-17 (Solve the quadratic equation)
4– 2y – 2y +y2
– 6y +17 =0
y2 – 10y +21
=0
(y – 7)(y – 3) =0
y= 7, y = 3
x = -2+ 3 , x = - 2 +7
= 1
= 5
Solving Daily Problem by Simultaneous Equation
Steps:
1.
Identify the two unknown involved in the situation
and represent the two unknown with suitable symbols.
2.
Form 2 equations based on the information given in
the situation
3.
Solve the quadratic equation.
Example:
1.
Given that the
perimeter of a rectangle is 26cm and its area is 40cm 2. Find the
length and width of the rectangle. (where length is greater than width)
Let
x be the length of rectangle
Let
y be the width of rectangle
x
+ x +y + y= 26
2x
+ 2y =26
(÷2) , x +y = 13 ------equation 1
xy =
40 -------- equation 2
From 1, x = 13- y ------ equation 3
Substitute
unknown of x into equation 2
(13
– y)( y) = 40
13y
– y2 – 40 = 0
-y2 +13 y -40 =0
(- y+ 8)( y- 5) =0
-y +8=0 , y- 5=0
-y =-8 , y=5
y = 8 , y=5
y = 8 , y=5
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